Tris(dibenzylideneacetone)dipalladium(0)-chloroform adduct,

Code: 366315-1G D2-231

Not available outside of the UK & Ireland.

Application

Tris(dibenzylideneacetone)dipalladium(0)-chloroform adduct (Pd2dba3·CHCl3) was used in the following studies:To compose the catal...


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Your Price
$158.85 1G

Not available outside of the UK & Ireland.

Application

Tris(dibenzylideneacetone)dipalladium(0)-chloroform adduct (Pd2dba3·CHCl3) was used in the following studies:To compose the catalytic system for the preparation of homoallylpalladium complexes.These complexes underwent in situ Stille type cross coupling with various vinyltin reagents to afford the cyclized products bearing allyl appendages.As palladium source in the asymmetric transformations of 3,4-epoxy-1-butene.As catalyst for the Heck cross-coupling reaction of iodobenzene with styrene.As cyclization catalyst.As catalyst for [2+2+2] cycloaddtion of didehydrotriphenylenes to the corresponding extended triphenylenes. As catalyst for the carbonylation of b,b-imidoyl iodides to the corresponding imidate esters used, in turn, to prepare cyclic, quaternary amino acids.

Application Guide for Palladium Catalyzed Cross-Coupling Reactions

General description

Tris(dibenzylideneacetone)dipalladium(0)-chloroform adduct (Pd2dba3·CHCl3) is reported to serve as effective precatalysts, or precursors to the active Pd(0) catalyst.

Packaging

1 g in glass bottle

250 mg in glass bottle

formsolid
InChI keyLNAMMBFJMYMQTO-FNEBRGMMSA-N
InChI1S/3C17H14O.CHCl3.2Pd/c3*18-17(13-11-15-7-3-1-4-8-15)14-12-16-9-5-2-6-10-16;2-1(3)4;;/h3*1-14H;1H;;/b3*13-11+,14-12+;;;
mp131-135 °C (lit.)
Quality Level100
reaction suitabilityreaction type: Buchwald-Hartwig Cross Coupling Reaction, reaction type: Hiyama Coupling, reaction type: Heck Reaction, reaction type: Sonogashira Coupling, reaction type: Suzuki-Miyaura Coupling, core: palladium, reaction type: Negishi Coupling, reaction type: Stille Coupling, reagent type: catalyst
SMILES string[Pd].[Pd].ClC(Cl)Cl.O=C(/C=C/c1ccccc1)C=Cc2ccccc2.O=C(/C=C/c3ccccc3)C=Cc4ccccc4.O=C(C=Cc5ccccc5)/C=C/c6ccccc6
Cas Number52522-40-4
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